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面向数据压缩的NOMA-MEC系统能耗最小化研究

施丽琴 刘璇 卢光跃

施丽琴, 刘璇, 卢光跃. 面向数据压缩的NOMA-MEC系统能耗最小化研究[J]. 电子与信息学报. doi: 10.11999/JEIT231033
引用本文: 施丽琴, 刘璇, 卢光跃. 面向数据压缩的NOMA-MEC系统能耗最小化研究[J]. 电子与信息学报. doi: 10.11999/JEIT231033
SHI Liqin, LIU Xuan, LU Guangyue. Research on Energy Consumption Minimization for a Data Compression Based NOMA-MEC System[J]. Journal of Electronics & Information Technology. doi: 10.11999/JEIT231033
Citation: SHI Liqin, LIU Xuan, LU Guangyue. Research on Energy Consumption Minimization for a Data Compression Based NOMA-MEC System[J]. Journal of Electronics & Information Technology. doi: 10.11999/JEIT231033

面向数据压缩的NOMA-MEC系统能耗最小化研究

doi: 10.11999/JEIT231033
基金项目: 国家自然科学基金(62301421)
详细信息
    作者简介:

    施丽琴:女,副教授,研究方向为无线供能通信、移动边缘计算

    刘璇:女,硕士生,研究方向为移动边缘计算

    卢光跃:男,教授,研究方向为宽带无线通信

    通讯作者:

    刘璇 liuxuan202309@126.com

  • 中图分类号: TN926

Research on Energy Consumption Minimization for a Data Compression Based NOMA-MEC System

Funds: The National Natural Science Foundation of China (62301421)
  • 摘要: 该文研究基于数据压缩的非正交多址-移动边缘计算(NOMA-MEC)系统中系统能耗最小化问题。考虑到部分压缩与卸载方案和基站端计算能力有限等条件,通过联合优化各用户的任务压缩和卸载比例、发射功率以及任务压缩时间等变量,建立一个系统能耗最小化优化问题。为了求解该问题,首先推导出各用户最佳发射功率的闭式表达式。接着利用连续凸逼近(SCA)方法对原问题的非凸约束进行近似,然后提出一个基于SCA的高效迭代算法来求解原问题,从而得到该系统的最佳资源分配方案。最后借助于计算机仿真对所提出方案的性能优势进行验证,仿真结果表明相比于其他基准方案,该文所提方案能有效降低系统能耗。
  • 图  1  系统模型

    图  2  系统时隙图

    图  3  本文所提算法的收敛性

    图  4  不同方案下系统能耗与各用户计算任务量的对比情况

    图  5  不同方案下系统能耗随基站端计算频率的变化情况

    图  6  不同用户接入数量下系统能耗随用户任务量的变化情况

    1  基于SCA的迭代算法

     输入:给定初始值$\left( {\left\{ {\alpha _k^0} \right\},\left\{ {\beta _k^0} \right\},t_{\rm o}^0,t_{\rm c}^0} \right)$;设置迭代次数$n = 1$、最大收敛次数$N$和收敛精度$\varepsilon $;设定循环中止标志${\text{Flag}} = 0$;
     输出:最优解$ \left( {\left\{ {\alpha _k^*} \right\},\left\{ {\beta _k^*} \right\},t_{\rm c}^{^*},\left\{ {p_k^*} \right\},t_{\rm o}^*} \right) $;最小系统能耗${E^*}$。
     (1) 根据$\left( {\left\{ {\alpha _k^0} \right\},\left\{ {\beta _k^0} \right\},t_{\rm o}^0,t_{\rm c}^0} \right)$计算得出中间变量$x_k^0$,进而计算出初始系统能耗为${E^0}$;
     (2) Repeat
     (3)  根据初始值计算得出$z_k^0$;
     (4)  在给定$\left( {\left\{ {z_k^0} \right\},t_{\rm o}^0} \right)$的情况下,利用CVX工具求解问题(21),并得到其最优解,即:$\left( {\left\{ {\alpha _k^n} \right\},\left\{ {x_k^n} \right\},t_{\rm c}{^n},t_{\rm o}^n} \right)$;
     (5)  根据上述所得到的最优解计算得出此时的最小系统能耗为${E^n}$;
     (6)  if $\left| {{E^n} - {E^{n - 1}}} \right| < \varepsilon $;
     (7)   此时最优解即为问题(18)的最优解,即:$ {\alpha }_{k}^{*}={\alpha }_{k}^{n};{\beta }_{k}^{*}={x}_{k}^{n}/{\alpha }_{k}^{n},\forall k\text{ };{t}_{\rm o}^{*}={t}_{\rm o}^{n};{t}_{\rm c}^{*}={t}_{\rm c}^{n} $;
          $ p_k^ * = {\sigma ^2}/{h_k}\left( {\exp \left( {z_k^0\ln 2/B{t_{\rm o}}} \right) - \exp \left( {z_{k - 1}^0\ln 2/B{t_{\rm o}}} \right)} \right) $;系统最小能耗为${E^*} = {E^n}$;
     (8)   输出问题(17)的最优解和系统最小能耗,即:$\left( {\left\{ {\alpha _k^*} \right\},\left\{ {\beta _k^*} \right\},\left\{ {p_k^*} \right\},t_{\rm o}^*,t_{\rm c}^*} \right)$;${E^*}$;设置${\text{Flag}} = 1$;
     (9)  else
     (10) 设置$ {\alpha }_{k}^{0}={\alpha }_{k}^{n};{x}_{k}^{0}={x}_{k}^{n},\forall k\text{ };{t}_{\rm o}^{0}={t}_{\rm o}^{n} $;$n = n + 1$;
     (11) end
     (12) until ${\text{Flag}} = 1$or$n = N$;
    下载: 导出CSV
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出版历程
  • 收稿日期:  2023-09-19
  • 修回日期:  2024-03-15
  • 网络出版日期:  2024-04-02

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