Joint Transmitting Subarray Partition and Beamforming Design Method Based on Two-Dimensional Phased-MIMO Radar
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摘要:
为了有效地抑制干扰信号并进一步提高雷达系统的性能，该文提出一种基于2维相控阵-MIMO雷达的联合发射子阵划分和波束形成设计方法。该方法首先将MIMO雷达系统的发射阵列等分成一定数目的非重叠子阵并给每个天线分配相同的发射能量，以确保发射信号具有恒模特性；其次，在一定的约束条件下，以最大化接收波束形成器的输出信干噪比为准则建立关于子阵结构、每个子阵对应的发射波束形成权矢量以及接收波束形成权矢量的优化模型，并采用循环迭代方法进行求解。仿真结果证实了所提方法的正确性和有效性。
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关键词:
- 相控阵-MIMO雷达 /
- 干扰抑制 /
- 发射子阵划分 /
- 波束形成
Abstract:In order to suppress effectively the interference signal and improve further the performance of radar system, a joint transmitting subarray partition and beamforming design method based on two-dimensional phased-MIMO radar is proposed. Firstly, the transmitting array of MIMO radar system is equally partitioned into a number of non-overlapping subarrays and the transmit power of each antenna is equal, so as to guarantee that the transmit signal has constant modulus characteristic. Then, the optimization model for subarray structure of transmitting array, transmit beamformer weight vectors and receive beamformer weight vector is established by maximizing the output signal-to-interference-plus-noise ratio of the receive beamformer under certain constraint conditions. Simulation results demonstrate the correctness and effectiveness of the proposed method.
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表 1 循环迭代算法流程
初始化：初始化子阵个数$K$，目标空间位置$({\theta _0},{\phi _0})$和散射系数${\gamma _0}$, $Q$个依赖于雷达系统发射波形的干扰的空间位置$\{ ({\theta _q},{\phi _q})\} _{q = 1}^Q$和散射
系数$\{ {\gamma _q}\} _{q = 1}^Q$, $P$个不依赖于雷达系统发射波形的干扰的空间位置$\{ ({\theta _p},{\phi _p})\} _{p = 1}^P$和功率$\{ \gamma _p^2\} _{p = 1}^P$，子阵结构${{{F}}^0}$，发射波束形成权矢量
$\{ \bar {{w}}_k^0\} _{k = 1}^K$，系统发射总能量$\eta $，终止阈值$\beta $；步骤 1 固定子阵结构${{{F}}^v}$和发射波束形成权矢量$\{ \bar {{w}}_k^v\} _{k = 1}^K$，根据式(19)计算接收波束形成权矢量${{{g}}^{v + 1}}$； 步骤 2 固定子阵结构${{{F}}^v}$和接收波束形成权矢量${{{g}}^{v + 1}}$，根据式(24)计算发射波束形成权矢量$\{ \bar {{w}}_k^{v + 1}\} _{k = 1}^K$； 步骤 3 固定发射波束形成权矢量$\{ \bar {{w}}_k^{v + 1}\} _{k = 1}^K$和接收波束形成权矢量${{{g}}^{v + 1}}$，根据式(29)和式(30)计算子阵结构${{{F}}^{v + 1}}$； 步骤 4 判断终止条件$|{\rm{SIN} }{ {\rm{R} }^{v + 1} } - {\rm{SIN} }{ {\rm{R} }^v}| \le \beta $是否满足，满足则终止，否则令$v = v+1$并重复步骤1至步骤4。 
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